Java

1365. How Many Numbers Are Smaller Than the Current NumberJavalizncu

lizncu

class Solution {
  public int[] smallerNumbersThanCurrent(int[] nums) {
    int[] count = new int[nums.length];

    for (int i = 0; i < nums.length; i++) {
      for (int j = 0; j < nums.length; j++) {
        if (nums[i] > nums[j]) {
          count[i]++;
        }
      }
    }

    return count;
  }
}