lmy

7. Reverse IntegerlmyC++

C++

class Solution {
 public:
  int reverse(int x) {
    int tmp = x;
    int res = 0;
    while (tmp) {
      int pop = tmp % 10;
      tmp /= 10;
      if (res > 2147483647 / 10 || (res == 2147483647 && pop > 7)) return 0;
      if (res < -2147483647 / 10 || (res == -2147483647 && pop < -8)) return 0;
      res = res * 10 + pop;
    }
    return res;
  }
};