Java

977. Squares of a Sorted ArrayJavalizncu

lizncu

class Solution {
  public int[] sortedSquares(int[] A) {
    if (A[0] >= 0) {
      for (int i = 0; i < A.length; i++) {
        A[i] = A[i] * A[i];
      }
      return A;
    }

    else if (A[A.length - 1] < 0) {
      int[] target = new int[A.length];
      int count = 0;

      for (int i = A.length - 1; i >= 0; i--) {
        target[count] = A[i] * A[i];
        count++;
      }

      return target;
    }

    else {
      int i = 0;
      while (!(A[i] < 0 && A[i + 1] >= 0)) {
        i++;
      }
      int k = i;
      int j = i + 1;

      int[] target = new int[A.length];
      int count = 0;

      while (k >= 0 && j < A.length) {
        if (A[k] * A[k] > A[j] * A[j]) {
          target[count] = A[j] * A[j];
          count++;
          j++;
        } else if (A[k] * A[k] < A[j] * A[j]) {
          target[count] = A[k] * A[k];
          count++;
          k--;
        } else {
          target[count] = target[count + 1] = A[k] * A[k];
          count += 2;
          k--;
          j++;
        }
      }

      if (count <= A.length - 1) {
        while (k >= 0) {
          target[count] = A[k] * A[k];
          count++;
          k--;
        }
        while (j < A.length) {
          target[count] = A[j] * A[j];
          count++;
          j++;
        }

        return target;
      }

      return target;
    }
  }
}